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Next: The Flexing Operation and Up: Flexagon Previous: Construction of a -Flexagon   Contents

Proper Flexagons

All proper flexagons, no matter what the cycle, have certain very important characteristics which may now be used to define the family of proper flexagons. The first important characteristic is found in the hinging order of all proper flexagons with complete $1-$flex cycles. Take, for example, a complete single cycle flexagon. The leaves of this flexagon are always hinged to one another in the hinge order 1 2 3 ...$(G-1)$ 0. This sequence is called the hinge sequence. This particular hinge sequence in which the numbers run consecutively from 1 to 0 mod. $G$ is characteristic of single cycle proper flexagons. The constant order is the other important characteristic. In single cycle $G-$flexagons it is always consecutive: 1 2 3 ...$(G-1)\; g$. If more cycles are added to the single cycle proper flexagon, some single leaves of the original flexagon become subpats. The subpats will contain all the sides of the new cycle, and since the new cycles are proper, the pat structures and hinge sequences of the subpats must be consecutive. It is true that the constant order and the hinge sequences of proper flexagons with more than one cycle are not consecutive, but the subpats will always be arranged consecutively from top to bottom, and the hinging of those subpats will always be consecutive.

It is important to notice that a $G-$flexagon with $G$ greater than 3 has more than one thumbhole, a thumbhole occurring when there is a positive hinge difference between two successive leaves in the pat structure. If we look at the pat structure of the ``simple'' proper pat, that is the pat from a single cycle flexagon (as opposed to a compound pat from a multi-cycle flexagon), we find that it may be either 1 or 1 2 3 ...$m$ where $m$ is the degree of the pat. The first pat has no thumbholes but in the second pat there will be thumbholes between leaves 1 and 2, 2 and 3, ...$m-1$ and $m$, or $m-1$ thumbholes per pat. If we designate these thumbholes from top to bottom 1 2 3 ...$(m-1)$ and then observe their operation, it will be seen that thumbhole 1 has a number 1 hinge associated with it and thus is used in a $1-$flex, while each succeeding thumbhole is used for a correspondingly higher order flex. After a flex and rotation, the thumbholes should be renumbered, but it should be observed that what was originally a number 1 thumbhole has now opened out to display a new side while the old number 2 thumbhole has been rotated in such a way that its hinge is in a number 1 position. The thumbhole at the very bottom has been generated by folding together the side which was on the back of the flexagon before flexing. This last thumbhole has a hinge in a $(G-1)$ position and may be used for flexing backwards. This discovery, that a given pat has $(m-1)$ thumbholes, makes it necessary for us to revise our definition of a pat. A pat, therefore, may be defined (in a circular way) as a series of subpats, each of which is a pat in itself; alternate subpats being inverted. The total number of subpats in a given unit is equal to the cycle. In proper flexagons, there are $(G-1)$ subpats in one pat of the unfolded flexagon and one subpat in the remaining pat.

Each single leaf of a simple proper flexagon unit is associated with two hinges and each hinge with two leaves. We may show this by writing down the constant order and indicating the hinges between two leaves as follows:

1 2 3 0
1; 2 3 4 - 1;

\begin{figure}\centering\begin{picture}(200,180)(0,0)
\put(0,0){\epsfxsize =200pt \epsffile{dibujos/fig701.eps}}
\end{picture}\\
Figure 7.1
\end{figure}

This is the constant order and hinge structure for a one-cycle proper tetraflexagon. But what would happen if we were to try to write the unit and hinge structures for a tetraflexagon with the map as in figure 7.1. Its constant order is 1 2; 4 3 while its hinge sequence is 1 3 1 0. Combined this would make:

1 3 1 0
1 2; 4 3 - 1;

This is a rather inconvenient method of notation, so instead, we will only associate one hinge with one leaf. Arbitrarily we will identify the first leaf with the first hinge of the hinge sequence. The leaf with pat number 2 will be associated with the second hinge, etc. The example above would then become:

1 3 0 1
1 2; 4 3.

Previously, we assigned hinge positions around a polygon in a certain direction of ascending values. This direction was clockwise and may be indicated around the face of a polygon by vectors drawn in the same direction along the edges of each side. A certain side will be designated as the zero position and it will be agreed that the side toward which the zero-side vector points to will be the ``1'' position. Then we may systematically follow the vectors and number each position with the number of vectors which are between it and the zero position (see figure 7.2a). These vectors may be drawn on both sides of all the leaves in the unit in such a way that when the unit is folded together, the vectors all point in the same direction. This ``orientation'' of the polygons of a unit will give us a frame of reference when the flexagon is unfolded. Before unfolding the flexagon, it would be well to note the relationship existing between the two hinges associated with a given leaf. If the hinge associated with the previous leaf (with respect to increasing pat numbering) was in an $a-$position and the one we are concerned with is in a $(a+x)-$position, the position this $(a+x)-$hinge holds with respect to the $a-$position hinge is $x$, the difference between the two hinges. This difference between two hinges attached to the same leaf is the ``hinge difference'' across that leaf. The advantage of the hinge difference is that it is independent of the arbitrarily assigned zero point for the hinge sequence. The hinge sequence for a one cycle proper flexagon is $1 2 3 \ldots G-1$, $0 1 2 3 \ldots \; $. The hinge difference across the first leaf is $1-0=1$, that across the second $2-1=1$, etc. Since the hinge sequence is consecutive the hinge differences will all be one. These hinge differences nay be written in the following manner:


Hinge difference 1 1 1 1   1
Hinge sequence 1 2 3 4 ... 0

\begin{figure}\centering\begin{picture}(260,130)(0,0)
\put(0,0){\epsfxsize =260pt \epsffile{dibujos/fig702.eps}}
\end{picture}\\
Figure 7.2
\end{figure}

The first ``1'' is the difference between an understood 0 hinge and the hinge in position one. The last ``I'' is the difference between $(G-1)$ and (0 mod. $G$) or just $G$. If we now open up the flexagon, we see this constant difference of 1 quite plainly. A given hinge is always one side removed from another hinge attached to the same leaf (see figure 7.2b). One will notice, however, that the direction is alternately left and right. This is because alternate leaves in the pat were inverted, as a result of the folding process. The vectors help keep track of things, for they point in a consistent manner around the unit polygons of the folded flexagon. The hinge of a certain leaf in the unfolded flexagon will always bear the same relationship to the vectors of that leaf as the hinge of any other leaf. That is, if we decide to travel along the plan in a given direction, the vectors we cross in going from one leaf to another will always point consistently toward or away from the next hinge. Whichever way they do point, they can always be made to point the other way by starting at the other end of the plan.

It is convenient for certain purposes which will become apparent to call the direction toward which the vector points + and the direction away from it -. Thus a $2-$hinge is +2 or $ ^+_+$ while a $(G-1)-$hinge is - and a $(G-2)-$hinge is ($ ^-_-$) (see figure 7.2a). The sign sequence for a proper flexagon of one cycle, then is +++...or $---$.... Here we see that + and - may be exchanged for one another just as in the triflexagons.


The Polygon System

There are $(G-1)$ possible hinges for a leaf with G sides. 7.1With proper flexagon leaves, however, there are only two possibilities if the flexagon is ``complete'', i. e. if it contains no incomplete cycles. To prove this, let us look at a proper complete single cycle $G-$flexagon. This flexagon, as we have seen has two possible sign sequences, +++ ...++ or $---\ldots--$. Now, if we add another cycle to this flexagon, we will be making a subpat out of what was previously a single leaf. If we added the new cycle between sides $(a)$ and $(a+1)$, the single leaf we must slit will have $(a)$ on one side and $(a+1)$ on the other. The $G$ possible places for attaching new cycles on the map correspond to the $G$ single leaves in a unit of a one cycle $G-$flexagon. If we do build subpats out of one or more of the single leaves of a single cycle $G-$flexagon, each subpat must have the same characteristics as the large pat in order for the flexagon to remain proper. Thus we know that the hinge difference between successive leaves in the subpat must consistently be either + or $-1$ and that the pat structure must be consecutive (these are the two requirements for a proper pat). We also know that the hinge difference across the whole subpat must be $+1$ when viewed from the top, with the vectors pointing clockwise since the leaf from which the subpat was generated had a +1 hinge difference. Since there will be $G-2$ sides and hence $G-2$ leaves added to the one leaf already present (as a former member of the large pat) there will be a total of $G-1$ leaves in the subpat. If the hinge differences must be consistently either +1 or $-1$ for each of the leaves, and if there are $G-1$ leaves, which must have a total hinge difference of +1, the individual hinge difference must be $-1$, since $0-(G-1) \mbox{mod.} G=+1$. If the individual hinge difference were +1, the total difference would be $0+(G-1)$ mod $G\; ^-_- -1,\; ^-_- +1$. Therefore, the hinge differences between the leaves of the subpat are negative with respect to those of the large pat. Similarly, if another subpat were to replace a leaf of this subpat, the individual hinge differences would be +1, since the hinge difference across a leaf of the first subpat is $-1$. The pat structure of any subpat will be inverted with respect to the next larger pat or subpat of which it is a member, just as was so with triflexagons. Therefore, when the leaves of a large pat are numbered $(m)-1, 1-2, \ldots (m-1)-(m)$ in ascending order from top to bottom, the subpats will be numbered in ascending order from bottom to top. Now, when such a compound pat is unwound, the progression of the number sequence from smaller to larger numbers in that portion of the plan which corresponds to the subpat will be just opposite the progression in that part of the plan in which the subpats were single leaves. This means that if we have a given complete one cycle $G-$flexagon whose number and sign sequences are:

+ + + + + + + +
(1) 3 (3) 5 ... (a) a+2 ... (G-1) 1
2 (2) 4 (4) ... a+1 (a+1) ... G (G)
(where $G$ is even) and we wish to insert another cycle adding $(G-2)$ sides between sides $(a)$ and $(a\!+\!1)$, the number and sign sequences will become:

+ + + + - - - - + + + +
(1) 3 (3) ... a (a+G-2) a+G-2 ... a+2 (a) a+G (a+G) a+G+2 ... (2G-3) 1
2 (2) 4 ... (a-1) a+G-l (a+G-3) ... (a+1) a+l (a+G-1) a+G+1 (a+G+1) ... 2G-2 (2G-2)
For instance, if we wanted to construct a complete order l4 octaflexagon in which the second cycle is added between 5 and 6 (figure 7.3a), the sign and number sequence for the plan would be:
+ + + + - - - - - - - + + +
(1) 3 (3) 5 (11) 11 (9) 9 (7) 7 (5) 13 (13) 1
2 (2) 4 (4) 12 (10) 10 (8) 8 (6) 6 (12) l4 (l4)
(a-1) (a+G-2) (a+l) (a) (a+G-l) (2G-2)

\begin{figure}\centering\begin{picture}(270,205)(0,0)
\put(0,0){\epsfxsize =270pt \epsffile{dibujos/fig703.eps}}
\end{picture}\\
Figure 7.3
\end{figure}

If we want to add another subpat to one of the leaves of the new subpat, its numbers would be reversed with respect to the already reversed numbers of the first subpat: they would increase from left to right and the signs would be +.

To figure out the plan by this method would be a long and tedious job, but it happens that one can use a shortcut device which is similar to the Tukey triangle system in the triflexagons. This shortcut makes use of a ``polygon system'' which is simply a generalization of the triangle system. The network is arrived at by drawing lines between the midpoints of the polygons making up the map and assigning numbers to the vertices thus formed (see figure 7.4a). The polygon system is followed in the same manner as the Tukey triangle system: The numbers of the vertices are written down in order to give the basic number sequence. The number sequence for the plan is arrived at by writing down the numbers of the basic number sequence alternately above and below a line and then adding 1 to each, placing the result on the other side of the line as shown:

+ + + + + + - - - + + -
1 3 3 11 11 1 7 7 5 9 9 55
2 2 4 10 12 12 8 6 6 8 10 4

A certain positive direction in the polygon system may be assigned. When a bend in the polygon system is made in that direction, the vertex at the bend is labeled +; when the bend is in the opposite direction, the vertex is -. Using this method, the sign and number sequences of any proper complete $G-$flexagon can be found, and its plan constructed in a manner similar to triflexagon plans: A system of oriented polygons is used. Choose one such polygon, and choose the side through which to enter that polygon. A + of the sign sequence means that the polygon must be left through the side toward which the vector of the side entered points; a - means the polygon must be left through the side away from the vector. The process is repeated using the next sign in the sign sequence, until the desired number of units have been manufactured (see figure 7.4b).

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\put(0,0){\epsfxsize =325pt \epsffile{dibujos/fig704.eps}}
\end{picture}\\
Figure 7.4
\end{figure}

A Tuckerman tree may be drawn to represent the map polygons, and the polygon system may be drawn about it; The Tuckerman tree for a given $G-$flexagon is not unique however, since a $2G-$flexagon can be built with the same tree. The polygon system will work for proper complete flexagons only, because it allows no more than two possible choices for hinging, where-as a leaf of class $n$ offers $(n - 1)$ possibilities. Only in the case of triflexagons will the polygon system account for all possibilities.


\begin{figure}\centering\begin{picture}(270,367)(0,0)
\put(0,0){\epsfxsize =270pt \epsffile{dibujos/fig705.eps}}
\end{picture}\\
Figure 7.5
\end{figure}

A complete proper $G-$flexagon of one cycle has a sign sequence composed entirely of + signs. If we add another cycle to this single cycle, one of the + signs is withdrawn from the sign sequence and in its place are put $(G-1)$ minus signs (see figure 7.5b). If we wish to continue, we may withdraw one of the minus signs and substitute $(G-1)$ plus signs (see figure 7.5c). Similarly, we may systematically reduce a flexagon with a number of cycles to one with a single cycle by exchanging $(G-1)$ adjacent signs of one kind for one of the opposite signs (see figure 7.5d). A given proper cycle always reduces by this method to $+-$. Since the + in the $+-$ represents a $1-$hinge and - represents $(G-1)-$hinge, we can add the two hinges: $1+(G-1) = G = 0 \mbox{ mod. } G$. Thus we have established that the sum of the signs of a given sign sequence must be congruent with $0 \mbox{ mod. } G$. In triflexagons, $G=3$ so the summation of the sign sequence equals $0 \mbox{ mod. } 3$, which has already been shown. If a given sign sequence is congruent to $0 \mbox{ mod. } G$, we may find out how many different flexagons can be made from it by reducing groups of $(G-1)$ of a given sign to one of the opposite sign.

Example:

The tetraflexagon sign sequence $--+++++++++++------+$ may be reduced to $+-$ in a number of different ways:

\begin{figure}\centering\begin{picture}(250,230)(0,0)
\put(0,-3){\epsfxsize =250pt \epsffile{dibujos/fig706.eps}}
\end{picture}\end{figure}

These are just three possibilities. There are more.


next up previous contents
Next: The Flexing Operation and Up: Flexagon Previous: Construction of a -Flexagon   Contents
Pedro 2001-08-22