Table 3.20:
Of the four relative alignments between an EBar and an F, the three highest let the EBar pass. The lowest removes them both leaving only a B to mark their presence.
1
EBar + F
2
EBar + F
3
EBar + F
4
B
Figure 3.39:
Left: EBar collides with F(1). Right: EBar collides with F(2).