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Since the square of a vector is not only a scalar, but the square of its Minkowski norm, it follows that it once divided by that norm, it is its own inverse, or that a unit vector is involutory. That is almost true, since the square of the vector can be negative; in that case the square root of the absolute value should be taken, and a minus sign should be appended to the inverse.
Pedro Hernandez
2004-02-28