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Projective space

The projective viewpoint would regard the defining equation $X' = M X + P$ as a fragment of a partitioned matrix equation:

\begin{eqnarray*}
\left[ \begin{array}{c} \xi' \\ \eta' \\ \hline \zeta' \end{a...
...egin{array}{c} \xi \\ \eta \\ \hline \zeta \end{array} \right].
\end{eqnarray*}



The componentwise equations,

\begin{eqnarray*}
\xi' & = & a \xi + b \eta + p \zeta \\
\eta' & = & c \xi + d \eta + q \zeta \\
\zeta' & = & 0 \xi + 0 \eta + 1 \zeta
\end{eqnarray*}



could be reconciled with the earlier equations by introducing the mapping

\begin{eqnarray*}
x = \frac{\xi}{\zeta} \\
y = \frac{\eta}{\zeta}
\end{eqnarray*}



Projective geometry is more comprehensive than affine geometry because there is no reason to restrict the transformation matrix to be upper triangular. If the more elaborate matrix

\begin{displaymath}\left[ \begin{array}{cc\vert c}
a & b & p \\
c & d & q \\
\hline
r & s & w
\end{array} \right] \end{displaymath}

were used, the projective transformation would read

\begin{eqnarray*}
x' & = & \frac{ax + by + p}{rx + sy + w} \\
y' & = & \frac{cx + dy + q}{rx + sy + w}.
\end{eqnarray*}



A special case would include uniform dilation

\begin{eqnarray*}
x' & = & \lambda x \\
y' & = & \lambda y.
\end{eqnarray*}



Generally speaking, a linear transformation of $n$ coordinates can be mapped into a projective transformation of $(n-1)$ coordinates, and conversely a nonlinear transformation of $n$ coordinates having the projective form can be mapped into a linear transformation of $n+1$ coordinates. In neither case is the transformation one-to-one, since all multiples of a vector have a common projective image, just as the counterimage of a projection has to include all multiples of any one of its points.


next up previous contents
Next: Mappings of a line Up: Affine and Projective Algebra Previous: Affine space   Contents
Pedro Hernandez 2004-02-28